Modeling, Functions, and GraphsXYZ Homework Edition

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6.5 Quadratic Inequalities

Solving Inequalities Graphically

In Functions and Their Graphs, we used graphs to solve equations and inequalities. The graphing technique is especially helpful for solving quadratic inequalities.

What are the solutions of the inequality x 2 + 1 < 0 ?

  1. ( − 1 , 1 )
  2. ( − ∞ , − 1 ) ∪ ( 1 , ∞ )
  3. All real numbers
  4. No solution
  1. Graph the function y = x 2 − 2 x − 9 in the window

    Xmin = − 0.4 Xmax = 9.4 Ymin = − 10 Ymax = 10

  2. Use the graph to solve the inequality x 2 − 2 x − 9 ≥ 6 .
  1. parabola for quadratic inequality
  2. x ≤ − 3 or x ≥ 5

In Example 1, we solved the inequality 256 t − 16 t 2 > 800 by comparing points on the graph of h = 256 − 16 t 2 with points on the line h = 800 . If one side of an inequality is zero, we can compare points on the graph with the line y = 0 , which is the x -axis.

Use a graph of y = 6 − x 2 to solve the inequalities.

  1. 6 − x 2 > 0
  2. 6 − x 2 ≤ 0
  1. − 6 < x < 6
  2. x ≤ − 6 or x ≥ 6

Which points on the parabola   y = a x 2 + b x + c   do we need to know to solve the inequality   a x 2 + b x + c > 0 ?

  1. The x -intercepts
  2. The y -intercept
  3. The vertex
  4. All of these

Because it is relatively easy to decide whether the y -coordinate of a point on a graph is positive or negative (the point lies above the x -axis or below the x-axis), we often rewrite a given inequality so that one side is zero.

Follow the steps below to solve the inequality   36 + 6 x − x 2 ≤ 20 .

  1. Rewrite the inequality so that the right side is zero.
  2. Graph the equation y = 16 + 6 x − x 2 .
  3. Locate the points on the graph with y -coordinate less than zero, and mark the x -coordinates of the points on the x -axis.
  4. Write the solution with interval notation.
  1. 16 + 6 x − x 2 ≤ 0
  2. parabola for quadratic inequality
  3. See graph
  4. ( − ∞ , − 2 ] ∪ [ 8 , ∞ )

Explain why you cannot write the solutions to x 2 − 4 > 0 as a single inequality.

Solving Quadratic Inequalities Algebraically

Although a graph is very helpful in solving inequalities, it is not completely necessary. Every quadratic inequality can be put into one of the forms

a x 2 + b x + c < 0 , b l a n k a x 2 + b x + c > 0 a x 2 + b x + c ≤ 0 , b l a n k a x 2 + b x + c ≥ 0

All we really need to know is whether the corresponding parabola y = a x 2 + b x + c opens upward or downward. Consider the parabolas shown below.

parabola opens up, the other opens down

The parabola in figure (a) opens upward. It crosses the x -axis at two points, x = r 1 and x = r 2 . At these points, y = 0 .

  • The graph lies below the x -axis between r 1 and r 2 , so the solutions to the inequality y < 0 lie between r 1 and r 2 .
  • The graph lies above the x -axis for x -values less than r 1 or greater than r 2 , so the solutions to the inequality y > 0 are x < r 1 or x > r 2 .

If the parabola opens downward, as in figure (b), the situation is reversed. The solutions to the inequality y > 0 lie between the x -intercepts, and the solutions to y < 0 lie outside the x -intercepts.

From the graphs, we see that the x -intercepts are the boundary points between the portions of the graph with positive y -coordinates and the portions with negative y -coordinates. To solve a quadratic inequality, we need only locate the x -intercepts of the corresponding graph and then decide which intervals of the x -axis produce the correct sign for y .

Why do we need to know whether tha parabola in QuickCheck 2 opens up or down?

  1. To decide whether to use > or < in the solution.
  2. To decide whether the solutions lie between the x -intercepts or outside them.
  3. To decide whether the solutions are positive or negative.
  4. To help us find the x -intercepts.

Solve x 2 < 20 .

  1. Write the inequality in standard form.
  2. Find the x -intercepts of the corresponding graph. Use extraction of roots.
  3. Make a rough sketch of the graph.
  4. Decide which intervals on the x -axis give the correct sign for y .

− 20 < x < 20

If we cannot find the x -intercepts of the graph by factoring or extraction of roots, we can use the quadratic formula.

What does the notation [ − 3 , 3 ] mean?

  1. The point with x -coordinate 3 and y -coordinate 3.
  2. x = 3 or x = − 3
  3. All real numbers between − 3 and 3 , excluding the endpoints.
  4. All real numbers between − 3 and 3 , including the endpoints.

Solve the inequality 10 − 8 x + x 2 > 4 .

  1. Write the inequality in standard form.
  2. Find the x -intercepts of the corresponding graph. Use extraction of roots.
  3. Make a rough sketch of the graph.
  4. Decide which intervals on the x -axis give the correct sign for y .

( − ∞ , 4 − 10 ] ∪ [ 4 + 10 , ∞ )

Explain how to use a graph to solve   x 2 + 4 x − 77 ≤ 0 .

Section Summary

Vocabulary

Look up the definitions of new terms in the Glossary.

  • Compound inequality
  • Interval notation

CONCEPTS

  1. We can use a graphical technique to solve quadratic inequalities.

STUDY QUESTIONS

  1. If a x 2 + b x > c for a particular value of x , what can you say about the graph of y = a x 2 + b x − c at that x -value?
  2. What are the only x -values at which the graph of y = a x 2 + b x + c can change sign?
  3. Explain the difference between an open interval and a closed interval.
  4. Explain what is wrong with the following "solution" to a quadratic inequality: 2 > x > 8 .
  5. The parabola y = x 2 + b x + c has x -intercepts at r 1 and r 2 , with r 1 < r 2 . What are the solutions of the inequality x 2 + b x + c > 0 ?
  6. The parabola y = x 2 + b x + c has x -intercepts at r 1 and r 2 , with r 1 < r 2 . What are the solutions of the inequality x 2 + b x + c ≤ 0 ?
  7. The parabola y = − x 2 + b x + c has x -intercepts at r 1 and r 2 , with r 1 < r 2 . What are the solutions of the inequality − x 2 + b x + c ≤ 0 ?
  8. The parabola y = − x 2 + b x + c has x -intercepts at r 1 and r 2 , with r 1 < r 2 . What are the solutions of the inequality − x 2 + b x + c > 0 ?

SKILLS

Practice each skill in the Homework problems listed.

  1. Solve a quadratic inequality graphically: #1–30
  2. Solve a quadratic inequality algebraically: #31–50
  3. Solve problems involving quadratic inequalities: #51–60

Homework 6.5

    1. Graph the function y = x 2 by hand on graph paper.
    2. Darken the portion of the x -axis for which y > 9 .
    3. Solve the inequality x 2 > 9 . Explain why x > 3 is incorrect as an answer.
    1. parabola for quadratic inequality
    2. See graph
    3. x > 3 or x < − 3 . It omits the solutions x < − 3 .
    1. Graph the function y = x 2 by hand on graph paper.
    2. Darken the portion of the x -axis for which y < 1 .
    3. Solve the inequality x 2 < 1 . Explain why x < 1 is incorrect as an answer.
    1. Graph the function y = x 2 − 2 x − 3 by hand on graph paper.
    2. Darken the portion of the x -axis for which y > 0 .
    3. Solve the inequality x 2 − 2 x − 3 > 0 .
    1. parabola for quadratic inequality
    2. See graph
    3. x > 3 or x < − 1
    1. Graph the function y = x 2 + 2 x − 8 by hand on graph paper.
    2. Darken the portion of the x -axis for which y < 0 .
    3. Solve the inequality x 2 + 2 x − 8 < 0 .

For problems 5-8, use the graphs provided to estimate the solutions to each equation and inequality.

    1. x 2 − 3 x − 180 = 0
    2. x 2 − 3 x − 180 > 0
    parabola
    1. − 12 , 15
    2. x < − 12 or x > 15
    1. 175 − 18 x − x 2 = 0
    2. 175 − 18 x − x 2 < 0
    parabola
    1. − 6 x 2 + 4.8 x − 0.9 = 0
    2. − 6 x 2 + 4.8 x − 0.9 ≥ 0
    parabola
    1. 0.3 , 0.5
    2. 0.3 ≤ x ≤ 0.5
    1. 5 x 2 + 7.5 x + 1.8 = 0
    2. 5 x 2 + 7.5 x + 1.8 ≤ 0
    parabola

For Problems 9-12, graph the parabola in the window

Xmin = − 9.4 ,     Xmax = 9.4 ,     Ymin = − 25 ,     Ymax = 25

Use the graph to solve the inequalities. Write your answers in interval notation.

  1. y = x 2 − 3 x − 18

    (For parts (c) and (d), it may be helpful to graph Y 2 = − 8 as well.)

    1. x 2 − 3 x − 18 > 0
    2. x 2 − 3 x − 18 < 0
    3. x 2 − 3 x − 18 ≤ − 8
    4. x 2 − 3 x − 18 ≥ − 8
    1. ( − ∞ , − 3 ) ∪ ( 6 , ∞ )
    2. ( − 3 , 6 )
    3. [ − 2 , 5 ]
    4. ( − ∞ , − 2 ] ∪ [ 5 , ∞ )
  2. y = 16 − 6 x − x 2

    (For parts (c) and (d), it may be helpful to graph Y 2 = 21 as well.)

    1. 16 − 6 x − x 2 ≥ 0
    2. 16 − 6 x − x 2 ≤ 0
    3. 16 − 6 x − x 2 < 21
    4. 16 − 6 x − x 2 > 21
  3. y = 16 − x 2

    (For parts (c) and (d), it may be helpful to graph Y 2 = 7 as well.)

    1. 16 − x 2 > 0
    2. 16 − x 2 < 0
    3. 16 − x 2 ≤ 7
    4. 16 − x 2 ≥ 7
    1. ( − 4 , 4 )
    2. ( − ∞ , − 4 ) ∪ ( 4 , ∞ )
    3. ( − ∞ , − 3 ] ∪ [ 3 , ∞ )
    4. [ − 3 , 3 ]
  4. y = x 2 − 9

    (For parts (c) and (d), it may be helpful to graph Y 2 = 16 as well.)

    1. x 2 − 9 ≥ 0
    2. x 2 − 9 ≤ 0
    3. x 2 − 9 > 16
    4. x 2 − 9 < 16

For Problems 13-18, solve the inequality by graphing. Use the following window settings:

Xmin = − 9.4 ,     Xmax = 9.4 ,     Ymin = − 15 ,     Ymax = 15

  1. ( x − 3 ) ( x + 2 ) > 0

    ( − ∞ , − 2 ) ∪ ( 3 , ∞ )

  2. ( x + 1 ) ( x − 5 ) > 0

  3. k ( 4 − k ) ≥ 0

    [ 0 , 4 ]

  4. − m ( 7 + m ) ≥ 0

  5. 6 + 5 p − p 2 < 0

    ( ∞ , − 1 ) ∪ ( 6 , ∞ )

  6. q 2 + 9 q + 18 < 0

For problems 19-24, solve the inequality by graphing. Use the following window settings:

Xmin = − 9.4 ,     Xmax = 9.4 ,     Ymin = − 62 ,     Ymax = 62

  1. x 2 − 1.4 x − 20 < 9.76

    ( − 4.8 , 6.2 )

  2. − x 2 + 3.2 x + 20 > 6.56

  3. 5 x 2 + 39 x + 27 ≥ 5.4

    ( − ∞ , − 7.2 ] ∪ [ 0.6 , ∞ )

  4. − 6 x 2 − 36 x − 20 ≤ 25.36

  5. − 8 x 2 + 112 x − 360 < 6.08

    ( − ∞ , 5.2 ) ∪ ( 8.8 , ∞ )

  6. 10 x 2 + 96 x + 180 > 17.2

For problems 25-30, solve the inequality by graphing. Choose a suitable window for each problem. Use the intersect feature to estimate your solutions accurate to one decimal place.

  1. x 2 > 12.2

    x < − 3.5 or x > 3.5

  2. x 2 ≤ 45

  3. − 3 x 2 + 7 x − 25 ≤ 0

    All x

  4. 2.4 x 2 − 5.6 x + 18 ≤ 0

  5. 0.4 x 2 − 54 x < 620

    − 10.6 < x < 145.6

  6. − 0.05 x 2 − 3 x > 76

For Problems 31-50, solve the inequality algebraically.Write your answers in interval notation, rounding to two decimal places if necessary.

  1. ( x + 3 ) ( x − 4 ) < 0

    ( − 3 , 4 )

  2. ( x + 2 ) ( x + 5 ) > 0

  3. 28 − 3 x − x 2 ≥ 0

    [ − 7 , 4 ]

  4. 32 + 4 x − x 2 ≤ 0

  5. 2 z 2 − 7 z > 4

    ( − ∞ , − 1 2 ) ∪ ( 4 , ∞ )

  6. 6 h 2 + 13 h < 15

  7. 64 − t 2 > 0

    ( − 8 , 8 )

  8. 121 − y 2 < 0

  9. v 2 < 5

    ( − 2.24 , 2.24 )

  10. t 2 ≥ 7

  11. 5 a 2 − 32 a + 12 ≥ 0

    ( − ∞ , 0.4 ] ∪ [ 6 , ∞ )

  12. 6 b 2 + 16 b − 9 < 0

  13. 4 x 2 + x ≥ − 2 x 2 + 2

    ( − ∞ , − 0.67 ) ∪ ( 0.5 , ∞ )

  14. 2 x 2 + 8 x ≤ − x 2 + 3

  15. x 2 − 4 x + 1 ≥ 0

    ( − ∞ , 0.27 ] ∪ [ 3.73 , ∞ )

  16. x 2 + 4 x + 2 ≤ 0

  17. − 3 − m 2 < 0

    All m

  18. 11 + n 2 < 0

  19. w 2 − w + 4 ≤ 0

    No solution

  20. − z 2 + z − 1 ≤ 0

In Problems 51–58,

  1. Solve each problem by writing and solving an inequality.
  2. Graph the equation and verify your solution on the graph.
  1. A fireworks rocket is fired from ground level. Its height in feet t seconds after launch is given by

    h = 320 t − 16 t 2

    During what time interval is the rocket higher than 1024 feet?

    1. 320 t − 16 t 2 > 1024 ; 4 < t < 16 : Between 4 and 16 seconds
    2. parabola for inequality
  2. A baseball thrown vertically reaches a height, h , in feet given by

    h = 56 t − 16 t 2

    where t is measured in seconds. During what time intervals is the ball between 40 and 48 feet high?

  3. The cost, in dollars, of manufacturing x pairs of garden shears is given by the function

    C = − 0.02 x 2 + 14 x + 1600

    for 0 ≤ x ≤ 700 . How many pairs of shears can be produced if the total cost must be kept under $ 2800 ?

    1. − 0.02 x 2 + 14 x + 1600 < 2800 ; [ 0 , 100 ) ∪ ( 600 , 700 ] : Either less than 100 or more than 600 shears.
    2. parabola for inequality
  4. The cost, in dollars, of producing x cashmere sweaters is given by the function

    C = x 2 + 4 x + 90

    How many sweaters can be produced if the total cost must be kept under $ 1850 ?

  5. The Locker Room finds that it sells 1200 − 30 p sweatshirts each month when it charges p dollars per sweatshirt. It would like its revenue from sweatshirts to be over $ 9000 per month. In what interval should it keep the price of a sweatshirt?

    1. p ( 1200 − 30 p ) > 9000 ; 10 < p < 30 : Between $ 10 and $ 30
    2. parabola for inequality
  6. Green Valley Nursery sells 120 − 10 p boxes of rose food per month at a price of p dollars per box. It would like to keep its monthly revenue from rose food over $ 350 . In what interval should it price a box of rose food?

  7. A group of cylindrical storage tanks must be 20 feet tall. If the volume of each tank must be between 500 π and 2880 π cubic feet, what are the possible values for the radius of a tank?

    1. 500 π < 20 π r 2 < 2880 π ; 5 < r < 12 ; The radius must be between 5 and 12 ft.
    2. parabola for inequality
  8. The volume of a cylindrical can should be between 21.2 and 21.6 cubic inches. If the height of the can is 5 inches, what values for the radius (to the nearest hundredth of an inch) will produce an acceptable can?

  9. A travel agency offers a group rate of $ 600 per person for a weekend in Lake Tahoe if 20 people sign up. For each additional person who signs up, the price for all participants is reduced by $ 10 per person.

    1. Write algebraic expressions for the size of the group and the price per person if x additional people sign up.
    2. Write a formula for the travel agency's total income as a function of x .
    3. What is the maximum income the travel agency can earn on the Lake Tahoe weekend? How many people should the agency enroll to achieve this income?
    4. How many people must sign up in order for the agency to bring in at least $ 15 , 750 ?
    5. Graph the income function and use the graph to verify your answers to parts (c) and (d).
    1. Size of group: 20 + x ; Price per person: 600 − 10 x
    2. I = ( 20 + x ) ( 600 − 10 x )
    3. $ 16 , 000 ;   20
    4. Between 5 and 35
    5. parabola for inequality
  10. A farmer inherits an apple orchard on which 60 trees are planted per acre. Each tree yields 12 bushels of apples. Experimentation has shown that for each tree removed per acre, the yield per tree increases by 1 2 bushel.

    1. Write algebraic expressions for the number of trees per acre and for the yield per tree if x trees per acre are removed.
    2. Write a formula for the total yield per acre as a function of x .
    3. What is the maximum yield per acre that can be achieved by removing trees? How many trees per acre should be removed to achieve this yield?
    4. How many trees should be removed per acre in order to harvest at least 850 bushels per acre?
    5. Graph the yield function and use the graph to verify your answers to parts (c) and (d).

Modeling, Functions, and Graphs by Katherine Yoshiwara (yoshiwarabooks.org), GNU Free Documentation License 1.2 or later. Adapted for the XYZ HTML edition with the authors' permission (recorded 2026-07-04). License: GFDL-1.2-or-later.

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