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3.4 Rational Exponents

Powers of the Form a m / n

In the last section, we considered powers of the form a 1 / n , such as x 1 / 3 and x 1 / 4 , and saw that a 1 / n is equivalent to the root a n . What about other fractional exponents? What meaning can we attach to a power of the form a m / n ?

Consider the power x 3 / 2 . Notice that the exponent 3 2 = 3 ( 1 2 ) , and thus by the third law of exponents, we can write

( x 1 / 2 ) 3 = x ( 1 / 2 ) 3 = x 3 / 2

In other words, we can compute x 3 / 2 by first taking the square root of x and then cubing the result. For example,

100 3 / 2 = ( 100 1 / 2 ) 3 Take the square root of 100. = 10 3 = 1000 Cube the result.

We will define fractional powers only when the base is a positive number.

x 3 4 means

_____

x 3 4 means the fourth root of x cubed

x 3 / 4 means

  1. the fourth root of x cubed
  2. the cube root of x to the fourth
  3. the 3/4 root of x
  4. the cube root of the fourth root of x

To compute a m / n , we can compute the n th root first, or the m th power, whichever is easier. For example,

8 2 / 3 = ( 8 2 ) 1 / 3 = 64 1 / 3 = 4

or

8 2 / 3 = ( 8 1 / 3 ) 2 = 2 2 = 4

Evaluate each power.

  1. 32 3 / 5 = _____
  2. 81 1.25 = _____
  1. 1 8
  2. 243

Evaluate each power.

  1. 32 3 / 5
  2. 81 1.25
  1. 1 8
  2. 243

Explain how to evaluate f ( x ) = x 3 4 for x = 625 by hand.

_____

Explain how to evaluate f ( x ) = x 3 / 4 for x = 625 by hand.

Power Functions

The graphs of power functions y = x m / n , where m / n is positive, are all increasing for x 0 . If m / n > 1 , the graph is concave up. If 0 < m / n < 1 , the graph is concave down. Some examples are shown below.

graphs of power functions

Perhaps the single most useful piece of information a scientist can have about an animal is its metabolic rate. The metabolic rate is the amount of energy the animal uses per unit of time for its usual activities, including locomotion, growth, and reproduction. The basal metabolic rate, or BMR, sometimes called the resting metabolic rate, is the minimum amount of energy the animal can expend in order to survive.

  1. Complete the table of values for the function f ( x ) = x 3 / 4 .
    x 0.1 0.2 0.5 1
    f ( x ) ____________________
    x 2 5 8 10
    f ( x ) ____________________
  2. Sketch the graph of the function.
  1. x 0.1 0.2 0.5 1
    f ( x ) 5.623 3.344 1.682 1
    x 2 5 8 10
    f ( x ) 0.595 0.299 0.210 0.178
  2. A graph is below.
power function
  1. Complete the table of values for the function f ( x ) = x 3 / 4 .
    x 0.1 0.2 0.5 1
    f ( x ) 0000 0000 0000 0000
    x 2 5 8 10
    f ( x ) 0000 0000 0000 0000
  2. Sketch the graph of the function.
  1. x 0.1 0.2 0.5 1
    f ( x ) 5.623 3.344 1.682 1
    x 2 5 8 10
    f ( x ) 0.595 0.299 0.210 0.178
  2. power function

Describe the concavity of the graph of f ( x ) = x a b , where a b > 0 .

_____

The graph is concave up if a b > 1 , and concave down if a b < 1 .

Describe the concavity of the graph of f ( x ) = x a / b , where a b > 0 .

  1. It is concave up.
  2. It is concave down.
  3. It is concave up if a b > 1 , and concave down if a b < 1 .
  4. It is concave up if a b < 1 , and concave down if a b > 1 .

More about Scaling

In Example we saw that large animals eat less than smaller ones, relative to their body weight. This is because the scaling exponent in Kleiber's rule is less than 1 . For example, let s represent the mass of a squirrel. The mass of a moose is then 600 s , and its metabolic rate is

B ( 600 s ) = 70 ( 600 s ) 0.75 = 600 0.75 70 s 0.75 = 121 B ( s )

or 121 times the metabolic rate of the squirrel. Metabolic rate scales as k 0.75 , compared to the mass of the animal.

In a famous experiment in the 1960s, an elephant was given LSD. The dose was determined from a previous experiment in which a 2.6 -kg cat was given 0.26 gram of LSD. Because the elephant weighed 2970 kg, the experimenters used a direct proportion to calculate the dose for the elephant:

0.26  g 2.6  kg = x  g 2970  kg

and arrived at the figure 297 g of LSD. Unfortunately, the elephant did not survive the experiment.

A human being weighs about 70 kg, and 0.2 mg of LSD is enough to induce severe psychotic symptoms. Use these data and Kleiber's rule to predict what dosage would produce a similar effect in an elephant.

About _____ mg

About 3.3 mg

A human being weighs about 70 kg, and 0.2 mg of LSD is enough to induce severe psychotic symptoms. Use these data and Kleiber's rule to predict what dosage would produce a similar effect in an elephant.

( 2970 70 ) 0.75 ( 0.2 ) 3.3 mg

Radical Notation

Because a 1 / n = a n , we can write any power with a fractional exponent in radical form as follows.

Write each expression in radical notation.

  1. 5 t 1.25
    _____
  2. 3 m 5 / 3
    _____
  1. 5 t 1.25 = 5 t 5 4
  2. 3 m 5 / 3 = 3 m 5 3

Write each expression in radical notation.

  1. 5 t 1.25
  2. 3 m 5 / 3
  1. 5 t 1.25 = 5 t 5 4
  2. 3 m 5 / 3 = 3 m 5 3

The notation a 0.6 means

_____

a 0.6 = a 3 5

The notation a 0.6 means

  1. a 6
  2. 1 a 6
  3. a 1 / 6
  4. a 3 / 5

Usually, we will want to convert from radical notation to fractional exponents, since exponential notation is easier to use.

Convert to exponential notation.

  1. 6 w 2 3 = _____
  2. v 3 s 5 4 = _____
  1. 6 1 / 3 w 2 / 3
  2. v 3 / 4 s 5 / 4

Convert to exponential notation.

  1. 6 w 2 3
  2. v 3 s 5 4
  1. 6 1 / 3 w 2 / 3
  2. v 3 / 4 s 5 / 4

Operations with Rational Exponents

Powers with rational exponents—positive, negative, or zero—obey the laws of exponents, which we discussed in Variation. You may want to review those laws before studying the following examples.

Simplify by applying the laws of exponents.

  1. x 1 / 3 ( x + x 2 / 3 ) = _____
  2. n 9 / 4 4 n 3 / 4 = _____
  1. x 4 / 3 + x
  2. n 3 / 2 4

Simplify by applying the laws of exponents.

  1. x 1 / 3 ( x + x 2 / 3 )
  2. n 9 / 4 4 n 3 / 4
  1. x 4 / 3 + x
  2. n 3 / 2 4

Which of the following is the correct way to evaluate 15 3 5 on a calculator?

_____

15 ( 3 ÷ 5 )

Which of the following is the solution to x 3 / 5 = 8 ?

  1. 8 2 / 5
  2. 8 3 / 5
  3. 8 5 / 3
  4. 8 5 / 3

Solving Equations

According to the third law of exponents, when we raise a power to another power, we multiply the exponents together. In particular, if the two exponents are reciprocals, then their product is 1 . For example,

( x 2 / 3 ) 3 / 2 = x ( 2 / 3 ) ( 3 / 2 ) = x 1 = x

This observation can help us to solve equations involving fractional exponents. For instance, to solve the equation

x 2 / 3 = 4

we raise both sides of the equation to the reciprocal power, 3 / 2 . This gives us

( x 2 / 3 ) 3 / 2 = 4 3 / 2 x = 8

The solution is 8 .

To solve the equation x 2 3 = k we should

_____

Raise both sides to the reciprocal of the exponent

To solve the equation x 2 / 3 = k we should

  1. Raise both sides to the negative of the exponent.
  2. Divide both sides by the exponent.
  3. Raise both sides to the reciprocal of the exponent.
  4. Raise the right side to the given exponent.

Solve the equation 3.2 z 0.6 9.7 = 8.7 . Round your answer to two decimal places.

Answer: _____

Isolate the power.

Raise both sides to the reciprocal power .

18.45

Solve the equation   3.2 z 0.6 9.7 = 8.7   . Round your answer to two decimal places.

Isolate the power, then raise both sides to the reciprocal power to get 18.45

Explain why x x = x 1.5 .

_____

Explain why x x = x 1.5 .

Section Summary

Vocabulary

Look up the definitions of new terms in the Glossary.

  • Rational exponent

CONCEPTS

  1. Rational exponents: a m / n = ( a 1 / n ) m = ( a m ) 1 / n ,       a > 0 ,     n 0.
  2. To compute a m / n , we can compute the n th root first, or the m th power, whichever is easier.
  3. The graphs of power functions y = x m / n , where m / n is positive, are all increasing for x 0 . If m / n > 1 , the graph is concave up. If 0 < m / n < 1 , the graph is concave down.
  4. Radical notation: a m / n = a m n = ( a n ) m .
  5. Powers with rational exponents—positive, negative, or zero—obey the laws of exponents.
  6. To solve the equation x m / n = k , we raise both sides to the power n / m .

STUDY QUESTIONS

  1. What does the notation a 0.98 mean?
  2. Explain how to evaluate the function f ( x ) = x 3 / 4 for x = 625 , without using a calculator.
  3. Explain why x x = x 1.5 .
  4. What is the first step in solving the equation ( x 2 ) 5 / 2 = 1.8 ?
  5. If the graph of f ( x ) = x a / b is concave down, and a / b > 0 , what else can you say about a / b ?

SKILLS

Practice each skill in the Homework problems listed.

  1. Simplify and evaluate powers with rational exponents: #1–4, 13–18
  2. Graph power functions with rational exponents: #19–22
  3. Solve radical equations: #23–38, 59 and 60
  4. Analyze power functions with rational exponents: #23–36
  5. Simplify expressions using the laws of exponents: #37–44, 57–70
  6. Solve equations involving rational exponents: #45–56

Homework 3.4

For the problems in Homework 3.4, assume that all variables represent positive numbers.

For Problems 1-4, evaluate each power.

  1. 81 3 / 4
  2. 125 2 / 3
  3. 625 0.75
  1. 27
  2. 25
  3. 125
  1. 8 2 / 3
  2. 64 2 / 3
  3. 243 0.4
  1. 16 3 / 2
  2. 8 4 / 3
  3. 32 1.6
  1. 1 64
  2. 1 16
  3. 1 256
  1. 125 4 / 3
  2. 32 3 / 5
  3. 100 2.5

For Problems 5–8, write each power in radical form.

  1. x 4 / 5
  2. b 5 / 6
  3. ( p q ) 2 / 3
  1. x 4 5
  2. 1 b 5 6
  3. 1 ( p q ) 2 3
  1. y 3 / 4
  2. a 2 / 7
  3. ( s t ) 3 / 5
  1. 3 x 0.4
  2. 4 z 4 / 3
  3. 2 x 0.25 y 0.75
  1. 3 x 2 5
  2. 4 z 4 3
  3. 2 x y 3 4
  1. 5 y 2 / 3
  2. 6 w 1.5
  3. 3 x 0.4 y 0.6

For Problems 9–12, write each expression with fractional exponents.

  1. x 2 3
  2. 2 a b 3 5
  3. 4 m p 7 6
  1. x 2 / 3
  2. 2 a 1 / 5 b 3 / 5
  3. 4 m p 7 / 6
  1. y 3
  2. 6 ( a b ) 3 5
  3. 2 n q 11 8
  1. ( a b ) 2 3
  2. 8 x 3 4
  3. R 3 T K 5
  1. ( a b ) 2 / 3
  2. 8 x 3 / 4
  3. 1 3 R T 1 / 2 K 5 / 2
  1. a b 2 3
  2. 5 y 2 3
  3. S 4 V H 3

For Problems 13–16, evaluate each root without using a calculator.

  1. 32 3 5
  2. 27 4 3
  3. 16 y 12 4
  1. 8
  2. 81
  3. 2 y 3
  1. 16 5 4
  2. 125 2 3
  3. 243 x 10 5
  1. a 8 b 16
  2. 8 x 9 y 27 3
  3. 81 a 8 b 12 4
  1. a 4 b 8
  2. 2 x 3 y 9
  3. 3 a 2 b 3
  1. a 10 b 36
  2. 64 x 6 y 18 3
  3. 32 x 25 y 5 5

For Problems 17–18, use a calculator to approximate each power or root to the nearest thousandth.

  1. 12 5 / 6
  2. 6 4 3
  3. 37 2 / 3
  4. 4.7 2.3
  1. 7.931
  2. 10.903
  3. 0.090
  4. 35.142
  1. 20 5 / 4
  2. 8 3 5
  3. 128 3 / 4
  4. 16.1 0.29

During a flu epidemic in a small town, health officials estimate that the number of people infected t days after the first case was discovered is given by

I ( t ) = 50 t 3 / 5

  1. Make a table of values for I ( t ) on the domain 0 t 20 . What is the range of the function on that domain?
    t 5 10 15 20
    I ( t ) 00000 00000 00000 00000
  2. How long will it be before 300 people are ill?
  3. Graph the function I ( t ) and verify your answer to part (b) on your graph.
  1. t 5 10 15 20
    I ( t ) 131 199 254 302

    Range: [ 0 , 302 ]
  2. 19.812 or about 20 days
  3. power function

The research division of an advertising firm estimates that the number of people who have seen their ads t days after the campaign begins is given by the function

N ( t ) = 2000 t 5 / 4

  1. Make a table of values for N ( t ) on the domain 0 t 20 . What is the range of the function on that domain?
    t 6 10 14 20
    N ( t ) 00000 00000 00000 00000
  2. How long will it be before 75 , 000 people have seen the ads?
  3. Graph the function N ( t ) and verify your answer to part (b) on your graph.

In Problems 21–22, graph each set of power functions in the suggested window and compare the graphs.

y 1 = x ,     y 2 = x 5 / 4 ,     y 3 = x 3 / 2 ,     y 4 = x 2 ,     y 5 = x 5 / 2

Xmin = 0 ,       Xmax = 6 ,       Ymin = 0 ,       Ymax = 10

All the graphs are increasing and concave up. For x > 1 , each graph increases more quickly than the previous one.

y 1 = x 2 / 5 ,     y 2 = x 1 / 2 ,     y 3 = x 2 / 3 ,     y 4 = x 3 / 4 ,     y 5 = x

Xmin = 0 ,       Xmax = 6 ,       Ymin = 0 ,       Ymax = 4

The surface to volume ratio is important in studying how organisms grow and why animals of different sizes have different characteristics.

  1. Write formulas for the volume, V , and the surface area, A , of a cube in terms of its length, L .
  2. Express the length of the cube as a function of its volume. Express the length of the cube as a function of its surface area.
  3. Express the surface area of the cube as a function of its volume.
  4. Express the surface to volume ratio of a cube in terms of its length. What happens to the surface to volume ratio as L increases?
  1. V = L 3 , A = 6 L 2
  2. L = V 1 / 3 , L = ( A 6 ) 1 / 2
  3. A = 6 V 2 / 3
  4. A V = 6 L . As L increases, the surface-to-volume ratio decreases.

Repeat Problem 23 for the volume and surface area of a sphere in terms of its radius, R .

  1. Write formulas for the volume, V , and the surface area, A , of a sphere in terms of its radius, R .
  2. Express the radius of the sphere as a function of its volume. Express the radius of the sphere as a function of its surface area.
  3. Express the surface area of the sphere as a function of its volume.
  4. Express the surface to volume ratio of a sphere in terms of its radius. What happens to the surface to volume ratio as R increases?

A brewery wants to replace its old vats with larger ones. To estimate the cost of the new equipment, the accountant uses the 0.6 rule for industrial costs, which states that the cost of a new container is approximately N = C r 0.6 , where C is the cost of the old container and r is the ratio of the capacity of the new container to the old one.

  1. If an old vat cost $ 5000 , graph N as a function of r .
  2. How much should the accountant budget for a new vat that holds 1.8 times as much as the old one?
  1. power function
  2. $ 7114.32

If a quantity of air expands without changing temperature, its pressure, in pounds per square inch, is given by P = k V 1.4 , where V is the volume of the air in cubic inches and k = 2.79 × 10 4 .

  1. Graph P as a function of V .
  2. Find the air pressure of an air sample when its volume is 50 cubic inches.

In the 1970s, Jared Diamond studied the number of bird species on small islands near New Guinea. He found that larger islands support a larger number of different species, according to the formula

S = 15.1 A 0.22

where S is the number of species on an island of area A square kilometers. (Source: Chapman and Reiss, 1992)

  1. Fill in the table.
    A 10 100 1000 5000 10 , 000
    S 000000 000000 000000 000000 000000
  2. Graph the function on the domain 0 < A 10 , 000 .
  3. How many species of birds would you expect to find on Manus Island, with an area of 2100 square kilometers? On Lavongai, whose area is 1140 square kilometers?
  4. How large must an island be in order to support 200 different species of bird?
  1. A 10 100 1000 5000 10 , 000
    S 25 42 69 98 115
  2. power function
  3. 81 , 71
  4. 126 , 000 sq km

The drainage basin of a river channel is the area of land that contributes water to the river. The table gives the lengths in miles of some of the world’s largest rivers and the areas of their drainage basins in square miles. (Source: Leopold, Wolman, and Miller 1992)

  1. Plot the data, using units of 100 , 000 on the horizontal axis and units of 500 on the vertical axis.
  2. The length, L , of the channel is related to the area, A , of its drainage basin according to the formula

    L = 1.05 A 0.58

    Graph this function on top of the data points.
  3. The drainage basin for the Congo covers about 1 , 600 , 000 square miles. Estimate the length of the Congo River.
  4. The Rio Grande is 1700 miles long. What is the area of its drainage basin?
RiverArea of
drainage basin
Length
Amazon 2 , 700 , 000 4300
Nile 1 , 400 , 000 4200
Mississippi 1 , 300 , 000 4100
Yangtze 580 , 000 2900
Volga 480 , 000 2300
St. Lawrence 460 , 000 1900
Ganges 440 , 000 1400
Orinoco 380 , 000 1400
Indus 360 , 000 2000
Danube 350 , 000 1800
Colorado 250 , 000 1700
Platte 72 , 000 800
Rhine 63 , 000 900
Seine 48 , 000 500
Delaware 12 , 000 200

The table at right shows the exponent, p , in the allometric equation

variable = k ( body mass ) p

for some variables related to mammals. (Source: Chapman and Reiss, 1992)

VariableExponent, p
Home range size 1.26
Lung volume 1.02
Brain mass 0.70
Respiration rate 0.26
  1. Match each equation to one of the graphs shown in the figure.
    four power functions
  2. Explain how the value of p in the allometric equation determines the shape of the graph. Consider the cases p > 1 , 0 < p < 1 , and p < 0 .
  1. Home range size: II, lung volume: III, brain mass: I, respiration rate: IV
  2. If p > 1 , the graph is increasing and concave up. If 0 < p < 1 , the graph is increasing and concave down. If p < 0 , the graph is decreasing and concave up.

The average body mass of a dolphin is about 140 kilograms, twice the body mass of an average human male.

  1. Using the allometric equations in Problem 29, calculate the ratio of the brain mass of a dolphin to that of a human.
  2. A good-sized brown bear weighs about 280 kilograms, twice the weight of a dolphin. Calculate the ratio of the brain mass of a brown bear to that of a dolphin.
  3. Use a ratio to compare the heartbeat frequencies of a dolphin and a human, and those of a brown bear and a dolphin. (See Example of Roots and Radicals.)

The gourd species Tricosanthes grows according to the formula L = a d 2.2 , where L is its length and d is its width. The species Lagenaria has the growth law L = a d 0.81 . (Source: Burton, 1998)

  1. By comparing the exponents, predict which gourd grows into a long, thin shape, and which is relatively fatter. Which species is called the snake gourd, and which is the bottle gourd?
  2. The snake gourd reaches a length of 2 meters ( 200 cm), with a diameter of only 4 cm. Find the value of a in its growth law.
  3. The bottle gourd is 10 cm long and 7 cm in diameter at maturity. Find the value of a in its growth law.
  4. The giant bottle gourd grows to a length of 23 cm with a diameter of 20 cm. Does it grow according to the same law as standard bottle gourds?
  1. Tricosanthes is the snake gourd and Lagenaria is the bottle gourd. Tricosanthes is thinner and Lagenaria is fatter.
  2. a 9.5
  3. a 2
  4. Yes

As a fiddler crab grows, one claw (called the chela) grows much faster than the rest of the body. The table shows the mass of the chela, C , versus the mass of the rest of the body, b , for a number of fiddler crabs. (Source: Burton, 1998)

b 65 110 170 205 300 360 615
C 6 15 30 40 68 110 240
  1. Plot the data.
  2. On the same axes, graph the function C = 0.007 b 1.63 . How well does the function fit the data?
  3. Using the function in part (b), predict the chela mass of a fiddler crab if the rest of its body weighs 400 mg.
  4. The chela from a fiddler crab weighs 250 mg. How much does the rest of its body weigh?
  5. As the body mass of a fiddler crab doubles from 100 mg to 200 mg, by what factor does the mass of its chela increase? As the body mass doubles from 200 mg to 400 mg?

The climate of a region has a great influence on the types of animals that can survive there. Extreme temperatures create difficult living conditions, so the diversity of wildlife decreases as the annual temperature range increases. Along the west coast of North America, the number of species of mammals, M , is approximately related to the temperature range, R , (in degrees Celsius) by the function M = f ( R ) = 433.8 R 0.742 . (Source: Chapman and Reiss, 1992)

  1. Graph the function for temperature ranges up to 30 C.
  2. How many species would you expect to find in a region where the temperature range is 10 C? Label the corresponding point on your graph.
  3. If 50 different species are found in a certain region, what temperature range would you expect the region to experience? Label the corresponding point on your graph.
  4. Evaluate the function to find f ( 9 ) , f ( 10 ) , f ( 19 ) , and f ( 20 ) . What do these values represent? Calculate the change in the number of species as the temperature range increases from 9 C to 10 C and from 19 C to 20 C. Which 1 increase results in a greater decrease in diversity? Explain your answer in terms of slopes on your graph.
  1. powe function
  2. 79 species
  3. 18.4 C
  4. f ( 9 ) 85 , f ( 10 ) 79 , f ( 19 ) 49 , f ( 20 ) 47 ; from 9 C to 10 C has the greater decrease, corresponding to the steeper slope.

A bicycle ergometer is used to measure the amount of power generated by a cyclist. The scatterplot shows how long an athlete was able to sustain various levels of power output. The curve is the graph of y = 500 x 0.29 , which approximately models the data. (Source: Alexander, 1992)

scatterplot and power function
  1. In this graph, which variable is independent and which is dependent?
  2. The athlete maintained 650 watts of power for 40 seconds. What power output does the equation predict for 40 seconds?
  3. The athlete maintained 300 watts of power for 10 minutes. How long does the equation predict that power output can be maintained?
  4. In 1979, a remarkable pedal-powered aircraft called the Gossamer Albatross was successfully flown across the English Channel. The flight took 3 hours. According to the equation, what level of power can be maintained for 3 hours?
  5. The Gossamer Albatross needed 250 watts of power to keep it airborne. For how long can 250 watts be maintained according to the given equation?

Inflating a Balloon at the start of this chapter gives data for the pressure inside April and Tolu's balloon as a function of its diameter. As the diameter of the balloon increases from 5 cm to 20 cm, the pressure inside decreases. Can we find a function that describes this portion of the graph?

  1. Pressure is the force per unit area exerted by the balloon on the air inside, or P = F A . Because the balloon is spherical, its surface area, A , is given by A = π d 2 . Because the force increases as the balloon expands, we will try a power function F = k d p , where k and p are constants, and see if this fits the data. Combine the three equations, P = F A , A = π d 2 , and F = k d p , to express P as a power function of d .
  2. Use your calculator's power regression feature to find a power function that fits the data. Graph the function P = 211 d 0.7 on top of the data. Do the data support the hypothesis that P is a power function of d ?
  3. What is the value of the exponent p in F = k d p ?
  1. P = k π d p 2
  2. scatterplot and power function

    The power function is a good fit on this interval.
  3. 1.3

The table shows the total number of frequent flyer miles redeemed by customers through the given year. (Source: www.hotelnewsresource.com)

  1. Plot the data, with t = 0 in 1980. What type of function might model the data?
  2. Graph the function f ( t ) = 3.13 t 2.33 on top of the data.
  3. Evaluate f ( 5 ) and f ( 25 ) . What do those values mean in this context?
  4. Use the regression equation to predict when the total number of miles redeemed will reach 10 trillion. Hint: How many billions make a trillion?
YearCumulative
miles redeemed
(billions)
1982 14.8
1984 85.3
1986 215.4
1988 387.5
1990 641.3
1992 975.2
1994 1455.9
1996 1996
1998 2670.8
2000 3379.1
2002 4123.6

For Problems 37–42, simplify by applying the laws of exponents. Write your answers with positive exponents only.

  1. 4 a 6 / 5 a 4 / 5
  2. 9 b 4 / 3 b 1 / 3
  1. 4 a 2
  2. 9 b 5 / 3
  1. ( 2 m 2 / 3 ) 4
  2. ( 5 n 3 / 4 ) 3
  1. 8 w 9 / 4 2 w 3 / 4
  2. 12 z 11 / 3 4 z 5 / 3
  1. 4 w 3 / 2
  2. 3 z 2
  1. ( 3 u 5 / 3 ) ( 5 u 2 / 3 )
  2. ( 2 v 7 / 8 ) ( 3 v 3 / 8 )
  1. k 3 / 4 2 k
  2. 4 h 2 / 3 3 h
  1. 1 2 k 1 / 4
  2. 4 3 h 1 / 3
  1. c 2 / 3 ( 2 3 c 2 )
  2. r 3 4 ( r 5 / 2 )

The incubation time for a bird's egg is a function of the mass, m , of the egg, and has been experimentally determined as

I ( m ) = 12.0 m 0.217

where m is measured in grams and I is in days. (Source: Burton, 1998)

  1. Calculate the incubation time (to the nearest day) for the wren, whose eggs weigh about 2.5 grams, and the greylag goose, whose eggs weigh 46 grams.
  2. During incubation, birds' eggs lose water vapor through their porous shells. The rate of water loss from the egg is also a function of its mass, and it appears to follow the rule

    W ( m ) = 0.015 m 0.742

    in grams per day. Combine the functions I ( m ) and W ( m ) to calculate the fraction of the initial egg mass that is lost during the entire incubation period.
  3. Explain why your result shows that most eggs lose about 18 % of their mass during incubation.
  1. Wren: 15 days, greylag goose: 28 days
  2. I ( m ) W ( m ) m = 0.18 m 0.041
  3. Because m 0.041 is close to m 0 , the fraction lost is close to 0.18 .

The incubation time for birds' eggs is given by

I ( m ) = 12.0 m 0.217

where m is the weight of the egg in grams, and I is in days. (See Problem 43.) Before hatching, the eggs take in oxygen at the rate of

O ( m ) = 22.2 m 0.77

in milliliters per day. (Source: Burton, 1998)

  1. Combine the functions I ( m ) and O ( m ) to calculate the total amount of oxygen taken in by the egg during its incubation.
  2. Use your result from part (a) to explain why daily oxygen consumption per unit mass is approximately inversely proportional to incubation time.
  3. Predict the daily oxygen consumption per gram of a herring gull's eggs, given that their incubation time is 26 days. (The actual value is 11 milliliters per day.)

For Problems 45–50, solve. Round your answers to the nearest thousandth if necessary.

x 2 / 3 1 = 15

x = 64

x 3 / 4 + 3 = 11

x 2 / 5 = 9

x = 1 243

x 3 / 2 = 8

2 ( 5.2 x 5 / 3 ) = 1.4

x 2.466

3 ( 8.6 x 5 / 2 ) = 6.5

Kepler's law gives a relation between the period, p , of a planet's revolution, in years, and its average distance, a , from the sun:

p 2 = K a 3

where K = 1.243 × 10 24 , a is measured in miles, and p is in years.

  1. Solve Kepler's law for p as a function of a .
  2. Find the period of Mars if its average distance from the sun is 1.417 × 10 8 miles.
  1. p = 1.115 × 10 12 a 3 / 2
  2. 1.88 years

Refer to Kepler's law, p 2 = K a 3 , in Problem 51.

  1. Solve Kepler's law for a as a function of p .
  2. Find the average distance from Venus to the sun if its period is 0.615 years.

If f ( x ) = ( 3 x 4 ) 3 / 2 , find x so that f ( x ) = 27 .

13 3

If g ( x ) = ( 6 x 2 ) 5 / 3 , find x so that g ( x ) = 32 .

If S ( x ) = 12 x 5 / 4 , find x so that S ( x ) = 20 .

0.665

If T ( x ) = 9 x 6 / 5 , find x so that T ( x ) = 15 .

For Problems 57–64, use the distributive law to find the product.

2 x 1 / 2 ( x x 1 / 2 )

2 x 3 / 2 2 x

x 1 / 3 ( 2 x 2 / 3 x 1 / 3 )

1 2 y 1 / 3 ( y 2 / 3 + 3 y 5 / 6 )

1 2 y 1 / 3 + 3 2 y 7 / 6

3 y 3 / 8 ( 1 4 y 1 / 4 + y 3 / 4 )

( 2 x 1 / 4 + 1 ) ( x 1 / 4 1 )

2 x 1 / 2 x 1 / 4 1

( 2 x 1 / 3 1 ) ( x 1 / 3 + 1 )

( a 3 / 4 2 ) 2

a 3 / 2 4 a 3 / 4 + 4

( a 2 / 3 + 3 ) 2

For Problems 65–70, factor out the smallest power from each expression. Write your answers with positive exponents only.

x 3 / 2 + x = x (     ?     )

x ( x 1 / 2 + 1 )

y y 2 / 3 = y 2 / 3 (     ?     )

y 3 / 4 y 1 / 4 = y 1 / 4 (     ?     )

y 1 y 1 / 4

x 3 / 2 + x 1 / 2 = x 3 / 2 (     ?     )

a 1 / 3 + 3 a 1 / 3 = a 1 / 3 (     ?     )

a 2 / 3 + a 1 / 3 1 a 1 / 3

3 b b 3 / 4 + 4 b 3 / 4 = b 3 / 4 (     ?     )

Modeling, Functions, and Graphs by Katherine Yoshiwara (yoshiwarabooks.org), GNU Free Documentation License 1.2 or later. Adapted for the XYZ HTML edition with the authors' permission (recorded 2026-07-04). License: GFDL-1.2-or-later.