#set document(title: "3.9 Scientific Notation", author: "OpenStax / XYZ Homework") #set page(width: 8.5in, height: auto, margin: 1in) #import "@preview/cetz:0.5.2" #set text(font: ("STIX Two Text", "Libertinus Serif", "New Computer Modern"), size: 10.5pt, lang: "en") #show math.equation: set text(font: ("STIX Two Math", "New Computer Modern Math")) #set par(justify: true, leading: 0.62em, spacing: 0.9em) #set enum(spacing: 1.1em) // room between list items so tall inline fractions don't collide #set list(spacing: 1.1em) #set table(stroke: 0.5pt + rgb("#c7ccd3")) #let BLUE = rgb("#183B6F") // brand navy — section bars + example/solution labels (white on navy 11.09:1) #let ORANGE = rgb("#A94509") // brand primary-700 — AA-safe deep orange for TEXT (5.93:1 on white; raw brand #F37021 is 2.94:1 and must never carry text) #let RED = rgb("#DC2626") // brand error-600 #let GREEN = rgb("#059669") // brand success-600 (decoration only; small green text uses green-text #007942) #show heading.where(level: 1): it => block(width: 100%, above: 0pt, below: 16pt, fill: gradient.linear(BLUE, rgb("#2C5AA0")), inset: (x: 14pt, y: 12pt), radius: 3pt, text(fill: white, weight: "bold", size: 19pt, it.body)) #show heading.where(level: 2): it => block(width: 100%, above: 18pt, below: 10pt, fill: BLUE, inset: (x: 10pt, y: 6pt), radius: 2pt, text(fill: white, weight: "bold", size: 12pt, it.body)) #show heading.where(level: 3): it => text(fill: ORANGE, weight: "bold", size: 12.5pt, it.body) #show heading.where(level: 4): it => text(fill: BLUE, weight: "bold", size: 10.5pt, it.body) #let examplebox(label, title, body) = block(width: 100%, breakable: true, fill: rgb("#EFF1F5"), stroke: 0.5pt + rgb("#CFDDF0"), radius: 4pt, inset: 10pt, above: 12pt, below: 12pt)[ #block(below: 6pt)[#box(fill: BLUE, inset: (x: 6pt, y: 2pt), radius: 2pt, text(fill: white, weight: "bold", size: 8.5pt, label)) #h(0.4em) #strong[#title]] #body] // rail = decorative left rule (raw brand token); labelcolor = AA-safe label text shade #let notebox(label, rail, labelcolor, tint, body) = block(width: 100%, breakable: true, fill: tint, stroke: (left: 3pt + rail), inset: (left: 10pt, rest: 8pt), radius: (right: 4pt), above: 11pt, below: 11pt)[ #text(fill: labelcolor, weight: "bold", size: 7.5pt, tracking: 0.5pt)[#upper(label)] #linebreak() #body] #let solutionbox(body) = block(above: 4pt, below: 8pt)[ #text(fill: BLUE, weight: "bold", size: 8.5pt)[Solution] #linebreak() #body] #let figph(msg) = block(width: 100%, height: 60pt, fill: rgb("#f6f7f9"), stroke: (paint: rgb("#c7ccd3"), dash: "dashed"), radius: 4pt, inset: 10pt)[ #align(center + horizon, text(fill: rgb("#889"), style: "italic", size: 9pt, msg))] // Standardize inlined figure sizes: measure the natural CeTZ canvas, then scale to a // consistent envelope (aspect-aware; see build_typst.py FIG_* constants). Unlike the // print preamble, dimensions are FLOORED: in an editor a user can trim a figure to a // degenerate 1-D shape (a bare line), and w/h or tw/w would then divide by zero. #let _STD_W = 3.5 #let _WIDE_W = 5.6 #let _MAX_H = 3.4 #let _ASPECT_WIDE = 2.2 #let _UPSCALE_MAX = 1.15 #let stdfig(body) = context { let m = measure(body) let w = calc.max(m.width / 1in, 0.01) let h = calc.max(m.height / 1in, 0.01) let tw = if w / h > _ASPECT_WIDE { _WIDE_W } else { _STD_W } let s = calc.min(tw / w, _MAX_H / h, _UPSCALE_MAX) align(center, box(scale(x: s * 100%, y: s * 100%, reflow: true, body))) } #show figure: set block(breakable: false) #set figure(gap: 8pt) #show figure.caption: set text(size: 8.5pt, fill: rgb("#555")) == 3.9#h(0.6em)Scientific Notation #figure(figph[An equation reads, 5 mol C over 1 times 6.02 times 10 to the 23rd atoms C over 1 mol C equals 3.01 times 10 to the 24th atoms C.], alt: "An equation reads, 5 mol C over 1 times 6.02 times 10 to the 23rd atoms C over 1 mol C equals 3.01 times 10 to the 24th atoms C.", caption: [Calculations in the sciences often involve numbers in scientific notation form.]) === Learning Objectives After completing this section, you should be able to: + Write numbers in standard or scientific notation. + Convert numbers between standard and scientific notation. + Add and subtract numbers in scientific notation. + Multiply and divide numbers in scientific notation. + Use scientific notation in computing real-world applications. The amount of information available on the Internet is simply incomprehensible. One estimate for the amount of data that will be on the Internet by 2025 is 175 Zettabytes. A single zettabyte is one billion trillion. Written out, it is 1,000,000,000,000,000,000,000. One estimate is that we’re producing 2.5 quintillion bytes of data per day. A quintillion is a trillion trillion, or, written out, 1,000,000,000,000,000,000. To determine how many days it takes to increase the amount of information that is on the Internet by 1 zettabyte, divide these two numbers, a zettabyte being 1,000,000,000,000,000,000,000, and 2.5 quintillion, being 2,500,000,000,000,000,000, shows it takes 400 days to generate 1 zettabyte of information. But doing that calculation is awkward with a calculator. Keeping track of the zeros can be tedious, and a mistake can easily be made. On the other end of the scale, a human red blood cell has a diameter of 7.8 micrometers. One micrometer is one millionth of a meter. Written out, 7.8 micrometers is 0.0000078 meters. Smaller still is the diameter of a virus, which is about 100 nanometers in diameter, where a nanometer is a billionth of a meter. Written out, 100 nanometers is 0.0000001 meters. To compare that to engineered items, a single transistor in a computer chip can be 14 nanometers in size (0.000000014 meters). Smaller yet is the diameter of an atom, at between 0.1 and 0.5 nanometers. Sometimes we have numbers that are incredibly big, and so have an incredibly large number of digits, or sometimes numbers are incredibly small, where they have a large number of digits after the decimal. But using those representations of the names of the sizes makes comparing and computing with these numbers problematic. That’s where scientific notation comes in. === Writing Numbers in Standard or Scientific Notation Form When we say that a number is in #strong[scientific notation], we are specifying the form in which that number is written. That form begins with an integer with an absolute value between 1 and 9, then perhaps followed the decimal point and then some more digits. This is then multiplied by 10 raised to some power. When the number only has one non-zero digit, the scientific notation form is the digit multiplied by 10 raised to an exponent. When the number has more than one non-zero digit, the scientific notation form is a single digit, followed by a decimal, which is then followed by the remaining digits, which is then multiplied by 10 to a power. The following numbers are written in scientific notation: #math.equation(block: true, alt: "1.45 times 10 cubed")[$1.45 × 10^(3)$] #math.equation(block: true, alt: "minus 8.345 times 10 to the power minus 4")[$− 8.345 × 10^(− 4)$] #math.equation(block: true, alt: "3 times 10 squared")[$3 × 10^(2)$] #math.equation(block: true, alt: "3.14159 times 10 to the power 0")[$3.14159 × 10^(0)$] The following numbers are not written in scientific notation: #math.equation(block: false, alt: "1.45")[$1.45$] because it isn't multiplied by 10 raised to a power #math.equation(block: false, alt: "minus 50.053 times 10 to the power 7")[$− 50.053 × 10^(7)$] because the absolute value of −50.053 is not at least 1 and less than 10 #math.equation(block: false, alt: "41.7 times 10 to the power 9")[$41.7 × 10^(9)$] because 41.7 is not at least 1 and less than 10 #math.equation(block: false, alt: "0.036 times 10 to the power minus 3")[$0.036 × 10^(− 3)$] because 0.036 is not at least one and less than 10 #examplebox("Example 1")[Identifying Numbers in Scientific Notation][ Which of the following numbers are in scientific notation? If the number is not in scientific notation, explain why it is not. + #math.equation(block: false, alt: "minus 9.67 times 10 to the power 20")[$− 9.67 × 10^(20)$] + #math.equation(block: false, alt: "145 times 10 to the power minus 8")[$145 × 10^(− 8)$] + #math.equation(block: false, alt: "1.45")[$1.45$] #solutionbox[ + The number #math.equation(block: false, alt: "minus 9.67 times 10 to the power 20")[$− 9.67 × 10^(20)$] is in scientific notation because the absolute value of −9.67 is at least 1 and less than 10. + The number #math.equation(block: false, alt: "145 times 10 to the power minus 8")[$145 × 10^(− 8)$] is not in scientific notation because 145 is not at least 1 and less than 10. + The number #math.equation(block: false, alt: "1.45")[$1.45$] is not in scientific notation form. Even though it is at least 1 but less than 10, it is not multiplied by 10 raised to a power. ] ] Some numbers are so large or so small that it is impractical to write them out fully. Avogadro’s number is important in chemistry. It represents the number of units in 1 mole of any substance. The substance many be electrons, atoms, molecules, or something else. Written out, the number is: 602,214,076,000,000,000,000,000. Another example of a number that is impractical to write out fully is the length of a light wave. The wavelength of the color blue is about 0.000000450 to 0.000000495 meters. Such numbers are awkward to work with, and so scientific notation is often used. We need to discuss how to convert numbers into scientific notation, and also out of scientific notation. Recall that multiplying a number by 10 adds a 0 to the end of the number or moves the decimal one place to the right, as in #math.equation(block: false, alt: "43 times 10 equals 430")[$43 × 10 = 430$] or #math.equation(block: false, alt: "3.89 times 10 equals 38.9")[$3.89 × 10 = 38.9$]. And if you multiply by 100, it adds two zeros to the end of the number or moves the decimal two places to the right, and so on. For example, #math.equation(block: false, alt: "38 times 100,000 equals 3,800,000")[$38 × 100,000 = 3,800,000$] and #math.equation(block: false, alt: "32.998 times 10,000 equals 329,980")[$32.998 × 10,000 = 329,980$]. Multiplying a number by 1 followed by some number of zeros just adds that many zeros to the end of the number or moves the decimal place that many places to the right. Numbers written as 1 followed by some zeros are just powers of 10, as in #math.equation(block: false, alt: "10 to the power 1 equals 10")[$10^(1) = 10$], #math.equation(block: false, alt: "10 squared equals 100")[$10^(2) = 100$], #math.equation(block: false, alt: "10 cubed equals 1,000")[$10^(3) = 1,000$], etc. Generally, #math.equation(block: false, alt: "10 to the power n equals 1 0...0 ︸ n")[$10^(n) = 1 limits(underbrace(0...0))_(n)$]. We can use this to write very large numbers. For instance, Avogadro’s number is 602,214,076,000,000,000,000,000, which can be written as #math.equation(block: false, alt: "6.02214076 times 10 to the power 23")[$6.02214076 × 10^(23)$]. The multiplication moves the decimal 23 places to the right. Similarly, when we divide by 10, we move the decimal one place to the left, as in #math.equation(block: false, alt: "the fraction 46.7 over 10 equals 4.67")[$frac(46.7, 10) = 4.67$]. If we divide by 100, we move the decimal two places to the left, as in #math.equation(block: false, alt: "the fraction 3.456 over 100 equals 0.03456")[$frac(3.456, 100) = 0.03456$]. In general, when you divide a number by a 1 followed by #math.equation(block: false, alt: "n")[$n$] zeros, you move the decimal #math.equation(block: false, alt: "n")[$n$] places to the left, as in #math.equation(block: false, alt: "the fraction 8,244.902 over 1,000,000 equals 0.008244902")[$frac(8","244.902, 1","000","000) = 0.008244902$]. This denominator could be written as #math.equation(block: false, alt: "10 to the power 6")[$10^(6)$]. If we use that in the expression and allow for negative exponents, rewrite the number as #math.equation(block: false, alt: "the fraction 8,244.902 over 1,000,000 equals the fraction 8,244.902 over 10 to the power 6 equals 8,244.902 times 10 to the power minus 6")[$frac(8","244.902, 1","000","000) = frac(8","244.902, 10^(6)) = 8,244.902 × 10^(− 6)$]. With this, we can write division by a 1 followed by #math.equation(block: false, alt: "n")[$n$] zeros as multiplication by 10 raised to #math.equation(block: false, alt: "‒ n")[$‒ n$]. Using that information, we can demonstrate how to convert from a number in standard form into scientific notation form. #strong[Case 1:] The number is a single-digit integer. In this case, the scientific notation form of the number is #math.equation(block: false, alt: "d i g i t times 10 to the power 1")[$d i g i t × 10^(1)$]. #strong[Case 2:] The absolute value of the number is less than 1. Follow the process below. - #strong[Step 1:] Count the number of zeros between the decimal and the first non-zero digit. Label this #math.equation(block: false, alt: "n")[$n$]. - #strong[Step 2:] Starting with the first non-zero digit of the number, write the digits. If the number was negative, include the negative sign. - #strong[Step 3:] If there is more than one digit, place the decimal after the first digit from Step 2. - #strong[Step 4:] Multiply the number from Step 3 by #math.equation(block: false, alt: "10 to the power n plus 1")[$10^(n + 1)$]. #strong[Case 3:] The absolute value of the number is 10 or larger. Follow the process below. - #strong[Step 1:] Count the number of digits that are to the left of the decimal point. Label this #math.equation(block: false, alt: "n")[$n$]. - #strong[Step 2:] Write the digits of the number without the decimal place, if one was present. If the number was negative, include the negative sign. - #strong[Step 3:] If there is more than one digit, place the decimal point after the first digit. - #strong[Step 4:] Multiply the number from Step 3 by #math.equation(block: false, alt: "10 to the power n minus 1")[$10^(n − 1)$]. #examplebox("Example 2")[Writing a Number in Scientific Notation][ Write the following numbers in scientific notation form: + 428.9 + −0.00000981 + 8 #solutionbox[ + Since the absolute value of 428.9 is 10 or larger, so we use the process from Case 3, above. #strong[Step 1:] There are three digits to the left of the decimal point, so #math.equation(block: false, alt: "n equals 3")[$n = 3$]. #strong[Step 2:] Write the digits of the number without the decimal place, which is 4289. #strong[Step 3:] Since there is more than one digit, place the decimal point after the first digit. We now have 4.289. #strong[Step 4:] Since #math.equation(block: false, alt: "n equals 3")[$n = 3$], we multiply 4.289 by 10 raised to the second power, #math.equation(block: false, alt: "4.289 times 10 squared")[$4.289 × 10^(2)$]. The scientific notation form of 428.9 is #math.equation(block: false, alt: "4.289 times 10 squared")[$4.289 × 10^(2)$]. + Since the absolute value of −0.00000981 is less than 1, we use the process from Case 2. #strong[Step 1:] The number of zeros between the decimal and the first non-zero digit is 5, so #math.equation(block: false, alt: "n equals 5")[$n = 5$]. #strong[Step 2:] We write the non-zero digits, including the negative sign, yielding −981. #strong[Step 3:] The decimal gets placed to the right of the first digit, resulting in −9.81. #strong[Step 4:] Since #math.equation(block: false, alt: "n equals 5")[$n = 5$], we multiply −9.81 by 10 raised to the fourth power, #math.equation(block: false, alt: "minus 9.81 times 10 to the power minus 6")[$− 9.81 × 10^(− 6)$]. The scientific notation form of −0.00000981 is #math.equation(block: false, alt: "9.81 times 10 to the power minus 6")[$9.81 × 10^(− 6)$]. + Since 8 is a single-digit integer, apply Case 1. The scientific notation form of 8 is #math.equation(block: false, alt: "8 times 10 to the power 1")[$8 × 10^(1)$]. ] ] When we write numbers in scientific notation form, we can manipulate the representation of the number by moving the decimal around, and making an appropriate change to the exponent of the 10. For instance, let’s look at #math.equation(block: false, alt: "145.8141 times 10 to the power 8")[$145.8141 × 10^(8)$]. If we wanted to move the decimal one place to the left, we’d have to increase the power of 10, as shown here: #math.equation(block: false, alt: "145.8141 times 10 to the power 8 equals 14.58141 times 10 to the power 9")[$145.8141 × 10^(8) = 14.58141 × 10^(9)$]. Since we moved the decimal one to the left, we balance that with moving the exponent up by one. Similarly, if we move the decimal one place to the right, we have to balance that by moving the exponent one to the left, or subtracting one from the exponent, as shown here: #math.equation(block: false, alt: "145.8141 times 10 to the power 8 equals 1458.141 times 10 to the power 7")[$145.8141 × 10^(8) = 1458.141 × 10^(7)$]. Generally, for a number in the form #math.equation(block: false, alt: "n u m b e r times 10 to the power n")[$n u m b e r × 10^(n)$]: - If you move the decimal to the left by #math.equation(block: false, alt: "k")[$k$] digits, you increase the exponent by #math.equation(block: false, alt: "k")[$k$]. - If you move the decimal to the right by #math.equation(block: false, alt: "k")[$k$] digits, you decrease the exponent by #math.equation(block: false, alt: "k")[$k$] digits. #examplebox("Example 3")[Increasing the Exponent][ Change #math.equation(block: false, alt: "456.142 times 10 to the power 5")[$456.142 × 10^(5)$] by moving the decimal two places to the left. #solutionbox[ Since we are moving the decimal to the left by two places, we increase the exponent of 10 by 2, so that the exponent is now 7. This gives us #math.equation(block: false, alt: "456.142 times 10 to the power 5 equals 4.56142 times 10 to the power 7")[$456.142 × 10^(5) = 4.56142 × 10^(7)$]. ] ] #examplebox("Example 4")[Decreasing the Exponent][ Change #math.equation(block: false, alt: "12.3 times 10 squared")[$12.3 × 10^(2)$] by moving the decimal five places to the right. #solutionbox[ Since we are moving the decimal to the right by five places, we decrease the exponent of 10 by 5, so that exponent is now −3. This give us #math.equation(block: false, alt: "12.3 times 10 squared equals 1230000.0 times 10 to the power minus 3")[$12.3 × 10^(2) = 1230000.0 × 10^(− 3)$]. ] ] === Converting Numbers from Scientific Notation to Standard Form In the previous section, converting a number from standard form to scientific notation was explored. Now, we explore converting from scientific notation back into standard form. Doing so involves moving the decimal according to the power of the 10. The decimal is moved a number of steps equal to the exponent of the 10. As demonstrated previously, when the exponent of the 10 is negative, the decimal is moved to the left and when the exponent of the 10 is positive, the decimal is moved to the right. #examplebox("Example 5")[Converting from Scientific Notation to Standard Form][ Convert the following into standard form: + #math.equation(block: false, alt: "2.78 times 10 to the power 9")[$2.78 × 10^(9)$] + #math.equation(block: false, alt: "9.04 times 10 to the power minus 8")[$9.04 × 10^(− 8)$] #solutionbox[ + Since the exponent is positive, the decimal moves nine places to the right, so #math.equation(block: false, alt: "2.78 times 10 to the power 9")[$2.78 × 10^(9)$] is #math.equation(block: false, alt: "2,780,000,000")[$2,780,000,000$]. + Since the exponent is negative, the decimal moves eight places to the left, so #math.equation(block: false, alt: "9.04 times 10 to the power minus 8")[$9.04 × 10^(− 8)$] is #math.equation(block: false, alt: "0.0000000904")[$0.0000000904$]. ] ] #notebox("Video", rgb("#DC2626"), rgb("#DC2626"), rgb("#f7f8fa"))[ #link("https://openstax.org/r/Converting_from_Standard_Form_to_Scientific_Notation_Form")[Converting from Standard Form to Scientific Notation Form] #link("https://openstax.org/r/Converting_from_Scientific_Notation_Form_to_Standard_Form")[Converting from Scientific Notation Form to Standard Form] ] #notebox("Tech Check", rgb("#183B6F"), rgb("#183B6F"), rgb("#EFF1F5"))[ #emph[Scientific Notation on a Calculator] Most scientific and graphing calculators come with the ability to directly convert from standard form to scientific notation. On the TI-83, it is accessed through the MODE menus. For a commonly used, free phone scientific calculator, the calculator can be forced to work in scientific notation mode through its settings. Some calculators, such as the Desmos online calculator, display scientific notation as a number times 10 to a power as you’ve seen in this section. However, some calculators indicate scientific notation by replacing the #math.equation(block: false, alt: "times 10 to the power n")[$× 10^(n)$] with an E (or EE) followed by the exponent. For example, shows what you may see on a TI-84. #figure(figph[Three Desmos online calculator screens show accessing E, using normal mode, and using sci mode. The first screen labeled normal float auto real radian HP has three rows. The first row reads, 2.53 times 10 power 12 on the left and 2.53 E 12 on the right. The second row reads, 2.53 E 12 on the left and 2.53 E 12 on the right. The third row reads, 2.53 E 1 on the left and 25.3 on the right. The second screen labeled normal float auto real radian HP has four rows. The first row reads, 411522630 times 3 on the left and 1234567890 on the right. The second row reads, 411522630 times 30 on the left and 1.23456789 E 10 on the right. The third row reads, 0.001 on the left and 0.001 on the right. The fourth row reads, 0.0009 on the left and 9 E minus 4 on the right. The third screen labeled sci float auto real radian HP has three rows. The first row reads, 2 times 5 on the left and 1 E 1 on the right. The second row reads, 12 times 42 on the left and 5.04 E 2 on the right. The third row reads, (2.3 times 10 power 3) (65 times 10 power 5) on the left and 1.495 E 10 on the right.], alt: "Three Desmos online calculator screens show accessing E, using normal mode, and using sci mode. The first screen labeled normal float auto real radian HP has three rows. The first row reads, 2.53 times 10 power 12 on the left and 2.53 E 12 on the right. The second row reads, 2.53 E 12 on the left and 2.53 E 12 on the right. The third row reads, 2.53 E 1 on the left and 25.3 on the right. The second screen labeled normal float auto real radian HP has four rows. The first row reads, 411522630 times 3 on the left and 1234567890 on the right. The second row reads, 411522630 times 30 on the left and 1.23456789 E 10 on the right. The third row reads, 0.001 on the left and 0.001 on the right. The fourth row reads, 0.0009 on the left and 9 E minus 4 on the right. The third screen labeled sci float auto real radian HP has three rows. The first row reads, 2 times 5 on the left and 1 E 1 on the right. The second row reads, 12 times 42 on the left and 5.04 E 2 on the right. The third row reads, (2.3 times 10 power 3) (65 times 10 power 5) on the left and 1.495 E 10 on the right.", caption: [Calculator screens]) ] === Adding and Subtracting Numbers in Scientific Notation To add or subtract numbers in scientific notation, the numbers first need to have the same exponent for the 10s. It is possible to add the following since the powers of 10 match: #math.equation(block: false, alt: "4.5 times 10 to the power 4 plus 3.15 times 10 to the power 4 equals 7.65 times 10 to the power 4")[$4.5 × 10^(4) + 3.15 × 10^(4) = 7.65 × 10^(4)$] Notice that the number parts were added, but the exponent part remained the same. This is due to the distributive property of the real numbers. The #math.equation(block: false, alt: "10 to the power 4")[$10^(4)$] is factored from the two terms, as shown: #math.equation(block: false, alt: "4.5 times 10 to the power 4 plus 3.15 times 10 to the power 4 equals open parenthesis 4.5 plus 3.15 close parenthesis times 10 to the power 4 equals 7.65 times 10 to the power 4")[$4.5 × 10^(4) + 3.15 × 10^(4) = ( 4.5 + 3.15 ) × 10^(4) = 7.65 × 10^(4)$] Numbers in scientific notation can be added or subtracted directly using a calculator. Simply enter the values in scientific form and set your calculator to display scientific notation. #examplebox("Example 6")[Adding and Subtracting Numbers in Scientific Notation with the Same Powers of 10][ Calculate the following: + #math.equation(block: false, alt: "3.8 times 10 to the power minus 3 plus 1.006 times 10 to the power minus 3")[$3.8 × 10^(− 3) + 1.006 × 10^(− 3)$] + #math.equation(block: false, alt: "9.61 times 10 to the power 8 minus 3.85 times 10 to the power 8")[$9.61 × 10^(8) − 3.85 × 10^(8)$] #solutionbox[ + Since the powers of 10 match, we use the distributive property of real numbers to factor 10#super[−3] from the numbers. We then add the number parts separately to get 4.806. #math.equation(block: false, alt: "3.8 times 10 to the power minus 3 plus 1.006 times 10 to the power minus 3 equals open parenthesis 3.8 plus 1.006 close parenthesis times 10 to the power minus 3 equals 4.806 times 10 to the power minus 3")[$3.8 × 10^(− 3) + 1.006 × 10^(− 3) = ( 3.8 + 1.006 ) × 10^(− 3) = 4.806 × 10^(− 3)$] + Since the powers of 10 match, we use the distributive property of real numbers to factor 10#super[8] from the numbers. We then subtract the number parts separately to get 5.76. #math.equation(block: true, alt: "9.61 times 10 to the power 8 minus 3.85 times 10 to the power 8 equals open parenthesis 9.61 minus 3.85 close parenthesis times 10 to the power 8 equals 5.76 times 10 to the power 8")[$9.61 × 10^(8) − 3.85 × 10^(8) = ( 9.61 − 3.85 ) × 10^(8) = 5.76 × 10^(8)$] ] ] Adding and subtracting in scientific notation is straightforward when the exponents are the same. There are two issues that can arise. The first issue is what to do if after adding or subtracting the result is not in scientific notation. #examplebox("Example 7")[Correcting an Answer to Scientific Notation After Adding or Subtracting][ Calculate the following: + #math.equation(block: false, alt: "7.03 times 10 to the power 13 plus 8.5 times 10 to the power 13")[$7.03 × 10^(13) + 8.5 × 10^(13)$] + #math.equation(block: false, alt: "4.3 times 10 to the power 21 minus 4.613 times 10 to the power 21")[$4.3 × 10^(21) − 4.613 × 10^(21)$] #solutionbox[ + Since the powers of 10 match, we add the number parts and multiply that by #math.equation(block: false, alt: "10 to the power 13")[$10^(13)$]: #math.equation(block: false, alt: "7.03 times 10 to the power 13 plus 8.5 times 10 to the power 13 equals open parenthesis 7.03 plus 8.5 close parenthesis times 10 to the power 13 equals 15.53 times 10 to the power 13")[$7.03 × 10^(13) + 8.5 × 10^(13) = ( 7.03 + 8.5 ) × 10^(13) = 15.53 × 10^(13)$]. However, #math.equation(block: false, alt: "15.53 times 10 to the power 13")[$15.53 × 10^(13)$] is not in scientific notation because the absolute value of 15.53 is more than 10. To put this number in scientific notation, the decimal needs to move one to the left. To balance that move, the power of 10 must be increased by 1. So, the answer in scientific notation is #math.equation(block: false, alt: "1.553 times 10 to the power 14")[$1.553 × 10^(14)$]. + Since the powers of 10 match, we add the number parts: #math.equation(block: false, alt: "4.3 times 10 to the power 21 minus 4.613 times 10 to the power 21 equals open parenthesis 4.3 minus 4.613 close parenthesis times 10 to the power 21 equals minus 0.313 times 10 to the power 21")[$4.3 × 10^(21) − 4.613 × 10^(21) = ( 4.3 − 4.613 ) × 10^(21) = − 0.313 × 10^(21)$] However, #math.equation(block: false, alt: "minus 0.313 times 10 to the power 21")[$− 0.313 × 10^(21)$] is not in scientific notation because it is less than 1. To put it in scientific notation, the decimal needs to move one to the right. To balance that move, the power of 10 must be decreased by 1. So, the answer in scientific notation is #math.equation(block: false, alt: "minus 3.13 times 10 to the power 20")[$− 3.13 × 10^(20)$]. ] ] The second issue that might be encountered when adding or subtracting is that the powers of 10 do not match. In that case, one of the numbers must be changed so that the powers of 10 match. It is easiest to make the smaller power of 10 larger to match the other power of 10. For example, to perform the following, #math.equation(block: false, alt: "4.5 times 10 to the power 5 plus 3.9 times 10 cubed")[$4.5 × 10^(5) + 3.9 × 10^(3)$], we’d change the #math.equation(block: false, alt: "3.9 times 10 cubed")[$3.9 × 10^(3)$] so that the power of 10 is 5. To do so, we need to increase the power of 10 and move the decimal in the number part two places to the left. That would alter #math.equation(block: false, alt: "3.9 times 10 cubed")[$3.9 × 10^(3)$] into #math.equation(block: false, alt: "0.039 times 10 to the power 5")[$0.039 × 10^(5)$]. We would use #math.equation(block: false, alt: "0.039 times 10 to the power 5")[$0.039 × 10^(5)$] in the addition problem, so that the exponents match, allowing the addition to occur. #math.equation(block: false, alt: "4.5 times 10 to the power 5 plus 3.9 times 10 cubed equals 4.5 times 10 to the power 5 plus 0.039 times 10 to the power 5 equals open parenthesis 4.5 plus 0.039 close parenthesis times 10 to the power 5 equals 4.539 times 10 to the power 5")[$4.5 × 10^(5) + 3.9 × 10^(3) = 4.5 × 10^(5) + 0.039 × 10^(5) = ( 4.5 + 0.039 ) × 10^(5) = 4.539 × 10^(5)$] The steps to take when the exponents of the 10s are not equal are: #strong[Step 1:] Increase the smaller exponent to equal the larger exponent. Label the amount increased as #math.equation(block: false, alt: "n")[$n$]. #strong[Step 2:] For the number with the smaller power of 10, move the decimal point of the number part to the left #math.equation(block: false, alt: "n")[$n$] places. #strong[Step 3:] Perform the addition or subtraction. #strong[Step 4:] If the result is not in scientific notation, adjust the number to be in scientific notation. #examplebox("Example 8")[Adding Numbers in Scientific Notation with Different Powers of 10][ Calculate the following: #math.equation(block: true, alt: "6.1 times 10 to the power 4 plus 4.8 times 10 to the power 5")[$6.1 × 10^(4) + 4.8 × 10^(5)$] #solutionbox[ #strong[Step 1:] The lower exponent is 4. To make this equal to the larger exponent, we increased it by 1. #strong[Step 2:] Since the smaller exponent was increased by 1, move the decimal one to the left, so the addition become #math.equation(block: false, alt: "6.1 times 10 to the power 4 plus 4.8 times 10 to the power 5 equals 0.61 times 10 to the power 5 plus 4.8 times 10 to the power 5")[$6.1 × 10^(4) + 4.8 × 10^(5) = 0.61 × 10^(5) + 4.8 × 10^(5)$]. #strong[Step 3:] Now add the numbers, #math.equation(block: false, alt: "0.61 times 10 to the power 5 plus 4.8 times 10 to the power 5 equals 5.41 times 10 to the power 5")[$0.61 × 10^(5) + 4.8 × 10^(5) = 5.41 × 10^(5)$] #strong[Step 4:] The result is in scientific notation, so no additional adjustment is necessary. #math.equation(block: true, alt: "6.1 times 10 to the power 4 plus 4.8 times 10 to the power 5 equals 5.41 times 10 to the power 5")[$6.1 × 10^(4) + 4.8 × 10^(5) = 5.41 × 10^(5)$] ] ] #examplebox("Example 9")[Subtracting Numbers in Scientific Notation with Different Powers of 10][ Calculate the following: #linebreak() #math.equation(block: false, alt: "7.9 times 10 to the power minus 15 minus 6.8 times 10 to the power minus 13")[$7.9 × 10^(− 15) − 6.8 × 10^(− 13)$] #solutionbox[ #strong[Step 1:] The lower exponent is −15 and the larger is −13. To make −15 equal to the larger exponent, we increased it by 2. #strong[Step 2:] Since the smaller exponent increased by 2, move the decimal two to the left. The subtraction changes to #math.equation(block: false, alt: "7.9 times 10 to the power minus 15 minus 6.8 times 10 to the power minus 13 equals 0.079 times 10 to the power minus 13 minus 6.8 times 10 to the power minus 13")[$7.9 × 10^(− 15) − 6.8 × 10^(− 13) = 0.079 × 10^(− 13) − 6.8 × 10^(− 13)$]. #strong[Step 3:] Subtract the numbers, #math.equation(block: false, alt: "0.079 times 10 to the power minus 13 minus 6.8 times 10 to the power minus 13 equals minus 6.721 times 10 to the power minus 13")[$0.079 × 10^(− 13) − 6.8 × 10^(− 13) = − 6.721 × 10^(− 13)$]. #strong[Step 4:] The result is in scientific notation, so no additional adjustment is necessary. #linebreak() #math.equation(block: false, alt: "7.9 times 10 to the power minus 15 minus 6.8 times 10 to the power minus 13 equals minus 6.721 times 10 to the power minus 13")[$7.9 × 10^(− 15) − 6.8 × 10^(− 13) = − 6.721 × 10^(− 13)$] ] ] === Multiplying and Dividing Numbers in Scientific Notation Multiplying and dividing numbers in scientific notation is somewhat easier than adding or subtracting, because the exponents of the 10s do not have to match. However, it is much more likely that the result will not be in scientific notation, and so that will have to be adjusted at the end. Generally, we multiply or divide the number parts of the two values, and then apply exponent rules to the 10 raised to the powers. To multiply two numbers in scientific notation: #strong[Step 1:] Multiply the number parts. #strong[Step 2:] Add the exponents of the 10s. #strong[Step 3:] The result is the answer from Step 1 times 10 raised to the answer from Step 2. #strong[Step 4:] If the number is not in scientific notation, adjust it appropriately. #examplebox("Example 10")[Multiplying Numbers in Scientific Notation][ Calculate the following: + #math.equation(block: true, alt: "open parenthesis 4.3 times 10 cubed close parenthesis times open parenthesis 1.8 times 10 to the power 7 close parenthesis")[$( 4.3 × 10^(3) ) × ( 1.8 × 10^(7) )$] + #math.equation(block: true, alt: "open parenthesis 5 times 10 to the power minus 1 cubed close parenthesis times open parenthesis 7.3 times 10 to the power 6 close parenthesis")[$( 5 × 10^(− 1) 3 ) × ( 7.3 × 10^(6) )$] #solutionbox[ + #strong[Step 1:] Multiply the number parts to get #math.equation(block: false, alt: "4.3 times 1.8 equals 7.74")[$4.3 × 1.8 = 7.74$]. #strong[Step 2:] Add the exponents of the 10s to get #math.equation(block: false, alt: "3 plus 7 equals 10")[$3 + 7 = 10$]. #strong[Step 3:] The result is then #math.equation(block: false, alt: "7.74 times 10 to the power 10")[$7.74 × 10^(10)$]. #strong[Step 4:] This number is already in scientific notation, so no additional adjustment is necessary, #math.equation(block: false, alt: "open parenthesis 4.3 times 10 cubed close parenthesis times open parenthesis 1.8 times 10 to the power 7 close parenthesis equals 7.74 times 10 to the power 10")[$( 4.3 × 10^(3) ) × ( 1.8 × 10^(7) ) = 7.74 × 10^(10)$]. + #strong[Step 1:] Multiply the number parts to get #math.equation(block: false, alt: "5 times 7.3 equals 36.5")[$5 × 7.3 = 36.5$]. #strong[Step 2:] Add the exponents of the 10s to get #math.equation(block: false, alt: "minus 13 plus 6 equals minus 7")[$− 13 + 6 = − 7$]. #strong[Step 3:] The result then is #math.equation(block: false, alt: "36.5 times 10 to the power minus 7")[$36.5 × 10^(− 7)$]. #strong[Step 4:]Since the number is not in scientific notation, it must be adjusted. To put #math.equation(block: false, alt: "36.5 times 10 to the power minus 7")[$36.5 × 10^(− 7)$] into scientific notation, the decimal moves one to the left, so the exponent would be increased by 1, giving #math.equation(block: false, alt: "3.65 times 10 to the power minus 6")[$3.65 × 10^(− 6)$]. #math.equation(block: true, alt: "open parenthesis 5 times 10 to the power minus 13 close parenthesis times open parenthesis 7.3 times 10 to the power 6 close parenthesis equals 3.65 times 10 to the power minus 6")[$( 5 × 10^(− 13) ) × ( 7.3 × 10^(6) ) = 3.65 × 10^(− 6)$] ] ] #notebox("Video", rgb("#DC2626"), rgb("#DC2626"), rgb("#f7f8fa"))[ #link("https://openstax.org/r/Multiplying_Numbers_in_Scientific_Notation")[Multiplying Numbers in Scientific Notation] ] === Dividing Numbers in Scientific Notation To divide two numbers that are in scientific notation: #strong[Step 1:] Divide the number parts. #strong[Step 2:] Subtract the exponent of the denominator from the exponent of the numerator. #strong[Step 3:] The answer is the result from Step 1 times 10 raised to the result from Step 2. #strong[Step 4:] If the number is not in scientific notation, adjust it appropriately. #examplebox("Example 11")[Dividing Numbers in Scientific Notation][ Calculate the following: + #math.equation(block: false, alt: "open parenthesis 8.4 times 10 to the power 31 close parenthesis / open parenthesis 2.1 times 10 to the power 7 close parenthesis")[$( 8.4 × 10^(31) ) #h(0.28em) / #h(0.28em) ( 2.1 × 10^(7) )$] + #math.equation(block: false, alt: "open parenthesis 4.14 times 10 to the power minus 13 close parenthesis / open parenthesis 8.28 times 10 to the power 9 close parenthesis")[$( 4.14 × 10^(− 13) ) #h(0.28em) / #h(0.28em) ( 8.28 × 10^(9) )$] #solutionbox[ + #math.equation(block: true, alt: "open parenthesis 8.4 times 10 to the power 31 close parenthesis / open parenthesis 2.1 times 10 to the power 7 close parenthesis")[$( 8.4 × 10^(31) ) #h(0.28em) / #h(0.28em) ( 2.1 × 10^(7) )$] #strong[Step 1:] Divide the number parts to get #math.equation(block: false, alt: "8.4 divided by 2.1 equals 4")[$8.4 ÷ 2.1 = 4$]. #strong[Step 2:] Subtract the exponent of the denominator from the exponent of the numerator to get #math.equation(block: false, alt: "37 minus 7 equals 24")[$37 − 7 = 24$]. #strong[Step 3:] The result is then #math.equation(block: false, alt: "4 times 10 to the power 24")[$4 × 10^(24)$]. #strong[Step 4:] This number is already in scientific notation, so no adjustment is necessary. #math.equation(block: false, alt: "open parenthesis 8.4 times 10 to the power 31 close parenthesis / open parenthesis 2.1 times 10 to the power 7 close parenthesis equals 4 times 10 to the power 24")[$( 8.4 × 10^(31) ) #h(0.28em) / #h(0.28em) ( 2.1 × 10^(7) ) = 4 × 10^(24)$] + #math.equation(block: true, alt: "open parenthesis 4.14 times 10 to the power minus 13 close parenthesis / open parenthesis 8.28 times 10 to the power 9 close parenthesis")[$( 4.14 × 10^(− 13) ) #h(0.28em) / #h(0.28em) ( 8.28 × 10^(9) )$] #strong[Step 1:] Divide the number parts to get #math.equation(block: false, alt: "4.14 divided by 8.28 equals 0.5")[$4.14 ÷ 8.28 = 0.5$]. #strong[Step 2:] Subtract the exponent of the denominator from the exponent of the numerator to get #math.equation(block: false, alt: "minus 13 minus 9 equals minus 22")[$− 13 − 9 = − 22$]. #strong[Step 3:] The result then is #math.equation(block: false, alt: "0.5 times 10 to the power minus 22")[$0.5 × 10^(− 22)$]. #strong[Step 4:] Since this number is not in scientific notation, it must be adjusted. To put #math.equation(block: false, alt: "0.5 times 10 to the power minus 22")[$0.5 × 10^(− 22)$] into scientific notation, the decimal needs to move one to the right, so the exponent is decreased by 1, giving #math.equation(block: false, alt: "5 times 10 to the power minus 23")[$5 × 10^(− 23)$]. #math.equation(block: false, alt: "open parenthesis 4.14 times 10 to the power minus 13 close parenthesis / open parenthesis 8.28 times 10 to the power 9 close parenthesis equals 5 times 10 to the power minus 23")[$( 4.14 × 10^(− 13) ) #h(0.28em) / #h(0.28em) ( 8.28 × 10^(9) ) = 5 × 10^(− 23)$] ] ] #notebox("Video", rgb("#DC2626"), rgb("#DC2626"), rgb("#f7f8fa"))[ #link("https://openstax.org/r/Dividing_Numbers_in_Scientific_Notation")[Dividing Numbers in Scientific Notation] ] === Using Scientific Notation in Computing Real-World Applications As noted at the start of this section, scientific notation is useful when the standard representation of a number is awkward or impractical, which occurs when the numbers being used are extremely large or extremely small. For example, Venus is 67,667,000 miles from the sun. In scientific notation, this is #math.equation(block: false, alt: "6.7667 times 10 to the power 7")[$6.7667 × 10^(7)$]. Planetary and galaxy distances is one set of numbers that is easier to express using scientific notation. #examplebox("Example 12")[Calculating Distances][ How much farther from the sun is Earth compared to Venus if Venus is #math.equation(block: false, alt: "6.7667 times 10 to the power 7")[$6.7667 × 10^(7)$] miles from the sun and Earth is #math.equation(block: false, alt: "9.1692 times 10 to the power 7")[$9.1692 × 10^(7)$] miles from the sun? #solutionbox[ To determine how much farther Earth is compared to Venus, we’d subtract the distances. #linebreak() #math.equation(block: false, alt: "9.1692 times 10 to the power 7 minus 6.7667 times 10 to the power 7 equals 2.4025 times 10 to the power 7")[$9.1692 × 10^(7) − 6.7667 × 10^(7) = 2.4025 × 10^(7)$]. So, Earth is #math.equation(block: false, alt: "2.4025 times 10 to the power 7")[$2.4025 × 10^(7)$] miles farther from the sun than Venus. ] ] #examplebox("Example 13")[Calculating Probability][ The probability of winning the Mega Millions lottery is published as #math.equation(block: false, alt: "3.304693 times 10 to the power minus 9")[$3.304693 × 10^(− 9)$]. The probability of being hit by lightning is approximated to be #math.equation(block: false, alt: "2 times 10 to the power minus 6")[$2 × 10^(− 6)$]. How many times more likely are you to be hit by lightning than win the Mega Millions? #solutionbox[ To find out how many times more likely you are to be hit by lightning, divide the probability of being hit by lightning by the probability of winning the Mega Millions. #math.equation(block: true, alt: "open parenthesis 2 times 10 to the power minus 6 close parenthesis / open parenthesis 3.304693 times 10 to the power minus 9 close parenthesis equals 6.609386 times 10 cubed")[$( 2 × 10^(− 6) ) #h(0.28em) / #h(0.28em) ( 3.304693 × 10^(− 9) ) = 6.609386 × 10^(3)$] #strong[Step 1:] Divide the number parts to get = #math.equation(block: false, alt: "0.6052")[$0.6052$] (rounded to the fourth digit). #strong[Step 2:] Subtract the exponent of the denominator from the exponent of the numerator to get #math.equation(block: false, alt: "minus 6 minus open parenthesis minus 9 close parenthesis equals 3")[$− 6 − ( − 9 ) = 3$]. #strong[Step 3:] The result then is #math.equation(block: false, alt: "0.6052 times 10 cubed")[$0.6052 × 10^(3)$]. #strong[Step 4:] Since this number is not in scientific notation, it must be adjusted. To put #math.equation(block: false, alt: "0.6052 times 10 cubed")[$0.6052 × 10^(3)$] into scientific notation, the decimal needs to move one place to the right, so the exponent is decreased by 1, giving #math.equation(block: false, alt: "6.052 times 10 squared")[$6.052 × 10^(2)$]. You are #math.equation(block: false, alt: "6.052 times 10 squared")[$6.052 × 10^(2)$], or 605.2, times more likely to be hit by lightning than you are to win the Mega Millions. ] ] #examplebox("Example 14")[Calculating Time and Length][ Sometimes it is entertaining to determine the time it takes for something to happen. Fingernails grow about #math.equation(block: false, alt: "8.032 times 10 to the power minus 11")[$8.032 × 10^(− 11)$] km per minute. How many kilometers long would fingernails be after #math.equation(block: false, alt: "6 times 10 to the power 4")[$6 × 10^(4)$] minutes? #solutionbox[ To find the length of the fingernails after the specified time, we multiply their rate of growth and the time they’ve grown. #math.equation(block: false, alt: "open parenthesis 8.032 times 10 to the power minus 11 close parenthesis times open parenthesis 6 times 10 to the power 4 close parenthesis equals 48.192 times 10 to the power minus 7 equals 4.8192 times 10 to the power minus 6")[$( 8.032 × 10^(− 11) ) × ( 6 × 10^(4) ) = 48.192 × 10^(− 7) = 4.8192 × 10^(− 6)$] So, after #math.equation(block: false, alt: "6 times 10 to the power 4")[$6 × 10^(4)$] minutes, the fingernails would be #math.equation(block: false, alt: "4.8192 times 10 to the power minus 6")[$4.8192 × 10^(− 6)$] km long. To put this in perspective, #math.equation(block: false, alt: "1 times 10 to the power minus 6")[$1 × 10^(− 6)$] km is a millimeter, and #math.equation(block: false, alt: "6 times 10 to the power 4")[$6 × 10^(4)$] minutes is about 4.16 days. So, after about 4.16 days, fingernails have grown about 4.8 millimeters. ] ] #examplebox("Example 15")[Calculating Data Generated][ As mentioned in the opening to this section, it is estimated that we’re producing 2.5 quintillion bytes of data per day. A good estimate is that there are 7.674 billion people on the planet. Convert both of those numbers to scientific notation, and then determine how much data is being generated per person each day. #solutionbox[ Written in standard form, 2.5 quintillion is 2,500,000,000,000,000,000. Changing that to scientific notation, move the decimal 18 places, so 2.5 quintillion bytes = #math.equation(block: false, alt: "2.5 times 10 to the power 18")[$2.5 × 10^(18)$] bytes. Writing 7.647 billion in scientific notation would be #math.equation(block: false, alt: "7.647 times 10 to the power 9")[$7.647 × 10^(9)$] because a billion is 1,000,000,000 = #math.equation(block: false, alt: "10 to the power 9")[$10^(9)$]. So, to find out how much data is being produced daily per person, we would divide these two numbers. #math.equation(block: false, alt: "the fraction 2.5 times 10 to the power 18 over 7.647 times 10 to the power 9 equals 0.327 times 10 to the power 9 equals 3.27 times 10 to the power 8")[$frac(2.5 × 10^(18), 7.647 × 10^(9)) = 0.327 × 10^(9) = 3.27 × 10^(8)$] In standard form, that’s 327,000,000 bytes per person, so 327 million bytes of data daily are being produced per person. ] ] #notebox("Video", rgb("#DC2626"), rgb("#DC2626"), rgb("#f7f8fa"))[ #link("https://openstax.org/r/Application_of_Scientific_Notation")[Application of Scientific Notation] ] === What Numbers Could Be Considered “Too Big” or “Too Small”? One wonders when the numbers we represent become too large or small for consideration. Perhaps the following examples put limits on what is meaningful. The number of particles in the known universe has been estimated at #math.equation(block: false, alt: "4 times 10 to the power 80")[$4 × 10^(80)$] particles. The smallest distance that has been measured is #math.equation(block: false, alt: "1 times 10 to the power minus 18 m")[$1 × 10^(− 18) #h(0.28em) upright(m)$], though the theoretical smallest measurable value is #math.equation(block: false, alt: "1 times 10 to the power minus 35 m")[$1 × 10^(− 35) #h(0.28em) upright(m)$]. The distance across the universe is #math.equation(block: false, alt: "4.4 times 10 to the power 26 m")[$4.4 × 10^(26) #h(0.28em) upright(m)$]. Considering what those numbers represent, the extreme largest and extreme smallest, they might be numbers that constrain what we should reasonably be expected to deal with. === Key Terms - scientific notation - standard notation === Key Concepts - Some numbers are so large or so small that writing the number out is clumsy and make it difficult to determine the true size of the number. Scientific notation makes the number more readable and make the relative size of the number immediately apparent. - A number written in scientific notation is a number at least 1 and smaller than 10 multiplied by 10 raised to an exponent. Converting between scientific notation and standard notation involves correctly applying multiplication and division by powers of 10, which in practice equates to understanding how moving the decimal point of a number impacts the exponent of 10. - Adding and subtracting numbers in base 10 requires the exponent of 10 in each number be the same. Once the numbers are converted to have the same exponent with the ten, then the numbers are added or subtracted as indicated, with the power of 10 remaining the same. If the result is not in scientific notation (for instance, the number has exceeded 10), then then number must be converted into scientific notation. - Multiplying and dividing numbers in scientific notation is done by multiplying or dividing the number parts, then multiplying or dividing the 10 raised to the power parts, then multiplying those two results. If the new number is not in scientific notation, then the result must be converted into scientific notation. === Videos - #link("https://openstax.org/r/Converting_from_Standard_Form_to_Scientific_Notation_Form")[Converting from Standard Form to Scientific Notation Form] - #link("https://openstax.org/r/Converting_from_Scientific_Notation_Form_to_Standard_Form")[Converting from Scientific Notation Form to Standard Form] - #link("https://openstax.org/r/Multiplying_Numbers_in_Scientific_Notation")[Multiplying Numbers in Scientific Notation] - #link("https://openstax.org/r/Dividing_Numbers_in_Scientific_Notation")[Dividing Numbers in Scientific Notation] - #link("https://openstax.org/r/Application_of_Scientific_Notation")[Application of Scientific Notation]